- The centripetal acceleration is given by ac = v^2 / r
- The speed is given by the circumference of the period, v= 2pi*r / T
r = 4.21 x 10^7, T = one day = 86400 seconds
V = [2pi * (4.21 x 10^7) ] / 86400 = 3062 m/s
a = (3062)^2 / (4.21 x 10^7) = .223 m/s^2
Question: A race car weight 1500 kg is running at a speed of 45 m/s (100 mph) through a circular corner of the track. The radius of the circle path is 180 m. What is centripetal force exert toward the center of the track?
- Centripetal force is given by Fc = mac = (m*v^2 ) / r
Fc = [1500 kg (45 m/s)^2] / 180 m
= 16875 N
No comments:
Post a Comment